If 2x^2 + 2x+3 =0 (you didn't mention =0. did you mean to?)
then use the quadratic formula as follows:
x=(-2±√[4-4(6)])/4
x=(-2±√[4-24])/4
x=(-2±√-20)/4
x=(-1±√-5)/2
use i (imaginary number=√-1)
x=(-1±i√5)/2
thats the answer.
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By using the quadratic equation formula: x = -5 and x = 3
To solve for x: 2x2 + 10 = 58 2x2 = 48 x2 = 24 x = √24 x = √4 × √6 x = 2√6
2x2 + 5x - 3 (2x - 1)(x + 3)
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)