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You try to find factors of 20 that add to 3.
Factors of 20 are 1/20, 2/10 & 4/5. You can't make 3 out of any of these so you have to use the quadratic formula:
x = (-b +/- (sqrt(b squared - 4 ac)))/2a
In your equation a = 1, b = -3 and c = -20
(3 +/- (sqrt(9 + 80)))/2
= (3 +/- sqrt 89)/2
= (3 +/- 9.434)/2
= 12.434/2 and -6.434/2
= 6.217 and -3.217 which are the values for x when your equation equals zero.
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How do you solve y equals x2-3x-20 using systems?
To solve the equation y = x^2 - 3x - 20 using systems, you can set up a system of equations by substituting y with x^2 - 3x - 20. This gives you the equation x^2 - 3x - 20 = 0. You can then solve this quadratic equation using factoring, the quadratic formula, or completing the square to find the values of x. Once you have the values of x, you can substitute them back into the original equation to find the corresponding values of y.
How do you solve negative 3x plus 5 equals 20?
-3x + 5 = 20 -3x = 15 x = -5
How do you factor x2-3x-28?
x2-3x-28
Evaluate -5x2 - 3x for x equals -2?
for x = -2: x2 = 4, -5x2 = -20; 3x = -6 giving -20 - (-6) = - 20 + 6 = -14.
Can you complete the square factor and use the quadratic formula to solve these two equations x2-4x-21 equals 0 and x2-3x-18 equals 0?
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
