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You try to find factors of 20 that add to 3.
Factors of 20 are 1/20, 2/10 & 4/5. You can't make 3 out of any of these so you have to use the quadratic formula:
x = (-b +/- (sqrt(b squared - 4 ac)))/2a
In your equation a = 1, b = -3 and c = -20
(3 +/- (sqrt(9 + 80)))/2
= (3 +/- sqrt 89)/2
= (3 +/- 9.434)/2
= 12.434/2 and -6.434/2
= 6.217 and -3.217 which are the values for x when your equation equals zero.
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How do you solve y equals x2-3x-20 using systems?
To solve the equation y = x^2 - 3x - 20 using systems, you can set up a system of equations by substituting y with x^2 - 3x - 20. This gives you the equation x^2 - 3x - 20 = 0. You can then solve this quadratic equation using factoring, the quadratic formula, or completing the square to find the values of x. Once you have the values of x, you can substitute them back into the original equation to find the corresponding values of y.
How do you solve negative 3x plus 5 equals 20?
-3x + 5 = 20 -3x = 15 x = -5
How do you factor x2-3x-28?
x2-3x-28
Evaluate -5x2 - 3x for x equals -2?
for x = -2: x2 = 4, -5x2 = -20; 3x = -6 giving -20 - (-6) = - 20 + 6 = -14.
Can you complete the square factor and use the quadratic formula to solve these two equations x2-4x-21 equals 0 and x2-3x-18 equals 0?
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
How do you solve y equals x2-3x-20 using systems?
To solve the equation y = x^2 - 3x - 20 using systems, you can set up a system of equations by substituting y with x^2 - 3x - 20. This gives you the equation x^2 - 3x - 20 = 0. You can then solve this quadratic equation using factoring, the quadratic formula, or completing the square to find the values of x. Once you have the values of x, you can substitute them back into the original equation to find the corresponding values of y.
How would you factor x to the power 4 plus 20 minus 3x?
(x2 + 3x + 5)(x2 - 3x + 4)
How do you solve x2 plus 3x plus 3 0?
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
How do you solve this problem it just says solve x2 plus 3y equals 7 3x plus y2 equals 3?
x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.
Solve the quadratic equation using factoring x2 3x 2 0?
x2+3x+2=0 (x+2)(x+1)=0 x=-2 or -1
How do you solve negative 3x plus 5 equals 20?
-3x + 5 = 20 -3x = 15 x = -5
How do you factor x2-3x-28?
x2-3x-28
How do you solve the problem x2 plus 3 multiplied by x plus 7?
The answer to this depends on what you mean by "solve". This is not an equation, merely an expression, so there is no solution to it. If by "solve" you actually mean "factor", this can not actually be done. x2 + 3x + 7 can not be factored. If you want solve it for a value of zero, that would be: x2 + 3x + 7 = 0 x2 + 3x + 9/4 = -7 + 9/4 x2 + 3x + 9/4 = -28/4 + 9/4 x2 + 3x + 9/4 = -19/4 (x + 3/2)2 = -19/4 x + 3/2 = ± i√19 / 2 x = (-3 ± i√19) / 2 If you are looking for the derivative of the equation, that would be 2x + 3 If you want the indefinite integral, it would be x3/3 + 3x2/2 + 7x + C
How do you solve x2 equals -3x?
5
Evaluate -5x2 - 3x for x equals -2?
for x = -2: x2 = 4, -5x2 = -20; 3x = -6 giving -20 - (-6) = - 20 + 6 = -14.
Can you complete the square factor and use the quadratic formula to solve these two equations x2-4x-21 equals 0 and x2-3x-18 equals 0?
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
How do you solve a square of a binomials?
Squaring a binomial can be done by writing the binomial twice and multiply using FOIL method.EX: (x+3)2 = (x+3)(x+3) = x2 +3x +3x +9 = x2 + 6x +9
