x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.
x2 - 3x + 2 = 0
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
If 3x - 1 = 11: To solve this equation, add 1 to each side of the equation to isolate x (3x -1 +1 = 11 + 1) and now the equation is 3x = 12. The next step is to divide both sides of the equation by 3 to find the value of x (3x / 3 = 12 / 3) for the answer x = 4. Not sure what you mean by x2 x, but you can substitute the value of x (which is 4) to solve.
x2+3x+1 = 0 Using the quadratic equation formula gives you: (x+2.618033989)(x+0.3819660113) = 0 So: x = -2.618033989 or x = -0.3819660113
X2 + 3X = 0X(X + 3) = 0--------------------X is the greatest common factorso,X = 0----------orX = - 3----------- assuming you might want to solve this type of problem some day
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
do you mean x2 + 3x + 2 ? Factors are (x +2)(x+1)
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
x = 2
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18