You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
120 5x4x3x2x1=120
Only one.
There are 7C4 = 7!/(4!*3!) = 7*6*5/(3*2*1) = 35 combinations.
There are 11,238,513 of them.
The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700
There are 5,461,512 such combinations.
There are infinitely many numbers and so infinitely many possible combinations.
10.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
The answer is 49C6 = 49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816
There are 120 permutations and 5 combinations.
There are 51C6 = 51*50*49*48*47*46/(6*5*4*3*2*1) = 18,009,460 combinations.
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
120 5x4x3x2x1=120
The answer is 31C5 = 31!/[26!5!] = 169,911
The number of combinations is nCr = (59*58*57*56*55)/(5*4*3*2*1) = 5006386