0
How many 4 digit combinations are there for the numbers 0-5 without having the same numbers twice?
There are 360 possible combinations.
Where n = how many numbers are available to choose from and r = the number chosen each time then:
Number of permutations = n! / (n - r)!
= 6! / (6 - 4)!
= (1 * 2 * 3 * 4 * 5 * 6) / (6 - 4)!
= 720 / 2! = 720 / (1 * 2) = 720 / 2 = 360.
(Note: this formula only applies where the order of the numbers is important and repetition is NOT allowed.)
What else can I help you with?
What are the different combinations of three digit numbers using 0-9?
9
What is a list of 5 digit combinations starting with a 3 and numbers can be repeated?
The number of four-digit combinations is 10,000 .Stick a '3' before each of them, and you have all the possible 5-digit combinations that start with 3.There are 10,000 of them. They run from 30,000 to 39,999 .
How many combinations are there for a 6 digit number using the numbers 2 4 5 9 7 6?
Without repetition, just one. In a combination the order of the numbers is irrelevant.
How many combinations of three one digit numbers equal 4?
5
How many combinations of 2 digit numbers can be produced from 01 99?
45.
How many 4 digit combanations using the numbers 1-7?
There are 840 4-digit combinations without repeating any digit in the combinations.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 5 digit combinations for numbers 1- 25?
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
What are all the number combinations for the numbers 1 through four?
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
Which one-digit numbers can be added to 26 without having to regroup?
only 2
How many different combinations are possible multiplying 8 different 7 digit numbers?
56 combinations. :)
How many four digit combinations are there for the numbers 1-6?
7
What are the different combinations of three digit numbers using 0-9?
9
How many unique 6 digit combinations can be found in 51 numbers?
Any 6 from 51 = 18,009,460 combinations
What is a list of 5 digit combinations starting with a 3 and numbers can be repeated?
The number of four-digit combinations is 10,000 .Stick a '3' before each of them, and you have all the possible 5-digit combinations that start with 3.There are 10,000 of them. They run from 30,000 to 39,999 .
How many combinations are there for a 6 digit number using the numbers 2 4 5 9 7 6?
Without repetition, just one. In a combination the order of the numbers is irrelevant.
