Any like well it depends if it adds to 20 so here is one from the top off my head
81821
8+8=16
1+1=2
2
16+4=20 there is common sense
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I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
Oh, dude, you're hitting me with the math questions, huh? Alright, so to find the number of 5-digit combinations from 1 to 20, you just do 20^5, which is like 3,200,000. So, yeah, there are 3,200,000 possible 5-digit combinations from 1 to 20.
There are 5,461,512 such combinations.
100
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