9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
There are 360 of them.
Through the magic of perms and coms the answer is 729
9000
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
There are 360 of them.
Through the magic of perms and coms the answer is 729
9000
34
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
If you exclude numbers starting with zero then the first digit must be between 1 and 9 (i.e. 9 combinations). The remaining 9 digits can be any value between 0 and 9 (i.e. 10 combinations).So you can have 9x109 = 9,000,000,000 combinations.
one
1, which is nine.
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
This is a factorial problem. The first number can be any of ten digits, the second any of nine (because you can't repeat a digit), the third any of eight and the fourth any of the remaining 7 digits. 10x9x8x7=5040 combinations.
In an average Sudoku puzzle there are nine larger boxes with nine small boxes inside each. The small boxes each get a number one through nine so that each larger box has nine different numbers in it. Therefore, nine different numbers are used and 81 numbers total.