Providing that they are whole numbers: 1*11 , 2*10, 3*9, 4*8, 5*7, 6*6 and 7*5 cm
9
There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
To find the number of different rectangles with a perimeter of 24 cm, we first use the formula for the perimeter ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting ( 2(l + w) = 24 ) simplifies to ( l + w = 12 ). The pairs of positive integers ( (l, w) ) that satisfy this equation are ( (1, 11), (2, 10), (3, 9), (4, 8), (5, 7), (6, 6) ). This results in 6 unique rectangles, considering length and width can be interchanged.
Depends what you are drawing on.
Infinite amounts.
9
are 48 m bola tha tumne 48 inches likh diya...
It depends what units you use for each side ! A 1cm x 15cm rectangle has a perimeter of 16cm. So does a 2cm x 4cm one ! If you start using millimetres, there are many more possibilities !
There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
There would be an infinite number of rectangles possible
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
To find the number of different rectangles with a perimeter of 24 cm, we first use the formula for the perimeter ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting ( 2(l + w) = 24 ) simplifies to ( l + w = 12 ). The pairs of positive integers ( (l, w) ) that satisfy this equation are ( (1, 11), (2, 10), (3, 9), (4, 8), (5, 7), (6, 6) ). This results in 6 unique rectangles, considering length and width can be interchanged.
the answer is 12
Depends what you are drawing on.
There are three possibilities.. 1 x 12... 2 x 6 & 3 x 4