There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
Depends what you are drawing on.
I don't understand why there are so many questions about rectangles' perimeter. You just add the length and the width and double your answer....
The only one I can think of is a square, where Length=Width=4.
There is an infinite number that can have that perimeter
There would be an infinite number of rectangles possible
thare is only 1 differint rectangles
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
the answer is 12
Infinite amounts.
Depends what you are drawing on.
I don't understand why there are so many questions about rectangles' perimeter. You just add the length and the width and double your answer....
The only one I can think of is a square, where Length=Width=4.
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
There are infinitely many possible rectangles. Let A be ANY number in the range (0,6] and let B = 12-A. Then a rectangle with width A and length B will have a perimeter of 2*(A+B) = 2*12 = 24 units. Since A is ANY number in the interval (0,6], there are infinitely many possible values for A and so infinitely many answers to the question.