The derivative of a function is the function's tangent function.So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)Now just make a plot for y = 4*sec2(2x) and you got your tangent function.
To integrate a function you find what the function you have is the derivative of. for example the derivative of x^2 is 2x. so the integral of 2x is x^2.
Y = 2X + 8 is a linear function of the form, Y = mX + c. A line.
8
The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.
The expression in the question "y -2x" is not a function.
If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
The [ 2x + 1 ] represents a function of 'y' .
The derivative of a function is the function's tangent function.So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)Now just make a plot for y = 4*sec2(2x) and you got your tangent function.
You cannot because the function is not well-defined. There is no equality symbol, the function In(2x) is not defined.
Yes.
If Y equals 2X - 2X - 24, then there is one root, and it is -24. The two 2X's cancel each other out.
To integrate a function you find what the function you have is the derivative of. for example the derivative of x^2 is 2x. so the integral of 2x is x^2.
Y = 2X + 8 is a linear function of the form, Y = mX + c. A line.
8
f(x)=2X-2
The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.