Q: How to sketch the grap of the function y -2x 2-4x-6?

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The derivative of a function is the function's tangent function.So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)Now just make a plot for y = 4*sec2(2x) and you got your tangent function.

To integrate a function you find what the function you have is the derivative of. for example the derivative of x^2 is 2x. so the integral of 2x is x^2.

Y = 2X + 8 is a linear function of the form, Y = mX + c. A line.

8

The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.

Related questions

The expression in the question "y -2x" is not a function.

If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.

The [ 2x + 1 ] represents a function of 'y' .

The derivative of a function is the function's tangent function.So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)Now just make a plot for y = 4*sec2(2x) and you got your tangent function.

You cannot because the function is not well-defined. There is no equality symbol, the function In(2x) is not defined.

Yes.

If Y equals 2X - 2X - 24, then there is one root, and it is -24. The two 2X's cancel each other out.

To integrate a function you find what the function you have is the derivative of. for example the derivative of x^2 is 2x. so the integral of 2x is x^2.

Y = 2X + 8 is a linear function of the form, Y = mX + c. A line.

8

f(x)=2X-2

The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.