Not enough information has been given to find the measure of the 3rd side of the triangle ABC but if it is in the form of an isosceles triangle then the 3rd side would work out as 6 units.
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
draw it out for ease. data: ab + 2 = ac bc-1 = ac therefore ab +2 = bc - 1 ab - bc = -3 perimeter is 62. /3 as most values are small difference. average distance is ~21. ab is smallest, guess it is 19. if so, ac would be 21. bc would be 22. does this add up? it actually does. i guess there is a mathematical way of doing this other than trial and error like the way i just did it, but i cannot see it right now
For two sides to be parallel they must not meet at a point (vertex). A triangle has only 3 sides. Let the vertices of a triangle be ABC; then the 3 sides of the triangle are AB, AC and BC. The sides AB and AC meet at vertex A, so they cannot be parallel. The sides AB and BC meet at vertex B, so they cannot be parallel. So Side AB is not parallel to AC (meets at vertex A) and not parallel to BC (meets at vertex B). The only possibility left is that side BC is parallel to side AC. But the sides BC and AC meet at vertex C so they cannot be parallel. Thus none of the sides of a triangle can be parallel.
15 cm
149
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
12
yes because ab plus bc is ac
9_or_yes">9 or yesA+ = 12
Consider a right triangle ABC as shown below. The right angle is at B, meaning angle ABC is 90 degrees. With the editor I have, I am not able to draw the line AC but imagine it to be there. By pythagorean theorem AC*2 = AB*2 + BC*2. The line AC is called the hypotenuse. Consider the angle ACB. The cosine of this angle is BC/AC, the sine is AB/AC and tangent is AB/BC. If you consider the angle BAC, then cosine of this angle is AB/AC, the sine is BC/AC and tangent is BC/AB. In general sine of an angle = (opposite side)/(hypotenuse) cosine of an angle = (adjacent side)/(hypotenuse) tangent of an angle = (opposite side)/(adjacent side) |A | | | | | | |______________________C B
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
If it's a right angle triangle then side ac is 10 units in length.
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
By using Pythagoras' theorem for a right angle triangle if side AB is the hypotenuse it is the square root of 149 which is about 12.207 rounded to three decimal places
Note!!!! ignore the S at the end these are the questions 1. side AC= 31 cm, side BC= 20 cm and angle B= 58 degrees 2. side AC= 21 cm, side BC= 28 cm and side AB= 32 cm 3. side AC= 8 cm and side AB= 10 cm please help last 3 questions of my homework. My teacher collects it =(
AC=5 AB=8 A=1 B=8 C=5 BC=40