Not enough information has been given to find the measure of the 3rd side of the triangle ABC but if it is in the form of an isosceles triangle then the 3rd side would work out as 6 units.
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
To find the possible length for side AB in triangle ABC with sides BC = 12 and AC = 21, we can use the triangle inequality theorem. The sum of the lengths of any two sides must be greater than the length of the third side. Therefore, we can write the inequalities: AB + BC > AC → AB + 12 > 21 → AB > 9 AB + AC > BC → AB + 21 > 12 → AB > -9 (which is always true) BC + AC > AB → 12 + 21 > AB → 33 > AB or AB < 33 Combining these, we get the inequality: 9 < AB < 33.
To find the length of side AC in a triangle, you can use the Law of Cosines if you know the lengths of the other two sides (AB and BC) and the included angle (∠B). The formula is: [ AC^2 = AB^2 + BC^2 - 2 \times AB \times BC \times \cos(\angle B) ] After calculating AC², take the square root to find AC. If you have a right triangle, you can simply use the Pythagorean theorem: [ AC = \sqrt{AB^2 + BC^2} ] (assuming AC is the hypotenuse).
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
draw it out for ease. data: ab + 2 = ac bc-1 = ac therefore ab +2 = bc - 1 ab - bc = -3 perimeter is 62. /3 as most values are small difference. average distance is ~21. ab is smallest, guess it is 19. if so, ac would be 21. bc would be 22. does this add up? it actually does. i guess there is a mathematical way of doing this other than trial and error like the way i just did it, but i cannot see it right now
149
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
12
yes because ab plus bc is ac
9_or_yes">9 or yesA+ = 12
Consider a right triangle ABC as shown below. The right angle is at B, meaning angle ABC is 90 degrees. With the editor I have, I am not able to draw the line AC but imagine it to be there. By pythagorean theorem AC*2 = AB*2 + BC*2. The line AC is called the hypotenuse. Consider the angle ACB. The cosine of this angle is BC/AC, the sine is AB/AC and tangent is AB/BC. If you consider the angle BAC, then cosine of this angle is AB/AC, the sine is BC/AC and tangent is BC/AB. In general sine of an angle = (opposite side)/(hypotenuse) cosine of an angle = (adjacent side)/(hypotenuse) tangent of an angle = (opposite side)/(adjacent side) |A | | | | | | |______________________C B
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
If it's a right angle triangle then side ac is 10 units in length.
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
By using Pythagoras' theorem for a right angle triangle if side AB is the hypotenuse it is the square root of 149 which is about 12.207 rounded to three decimal places
Note!!!! ignore the S at the end these are the questions 1. side AC= 31 cm, side BC= 20 cm and angle B= 58 degrees 2. side AC= 21 cm, side BC= 28 cm and side AB= 32 cm 3. side AC= 8 cm and side AB= 10 cm please help last 3 questions of my homework. My teacher collects it =(
AC=5 AB=8 A=1 B=8 C=5 BC=40