seven is 0dd only even number can be divided by two like 2,4,6,8,10,10 and so on odd numbers are 1,3,5,7,9,11,13 and so on
In 100 yrs there are 5 odd days..... out of 100 yrs totally 24 leap yrs.: no other century is not leap yr 100 yrs= 24 leap yrs * 76 ord yrs 1 leap yrs= 2 0dd days ord yrs= 1 0dd days 100= 24*2+ 76 =124/7 =5 odd days
You want: P(even) * P(even) * P(even) * P(even). P(even) = 3/6 or 1/2. Therefore probability even on 4 rolls is: 1/2 * 1/2 * 1/2 * 1/2 = 1/16 = 0.0625.
When a die is cast half the possible numbers are even. Therefore the probability is:Probability that die 1 is even = 1/2Probability that die 2 is even = 1/2Probability that both are even = 1/2 * 1/2 = 1/4.
1 in 4. Your choices are to have an odd or even total, which is a 1 in 2 chance. In order to get an even number, you have to have both die even or odd. So that cuts the 1 in 2 in half, giving you a 1 in 4 chance of both dice being even. (1 in 2 for even times 1 in 2 both even gives you 1 in 4.)
seven is 0dd only even number can be divided by two like 2,4,6,8,10,10 and so on odd numbers are 1,3,5,7,9,11,13 and so on
In 100 yrs there are 5 odd days..... out of 100 yrs totally 24 leap yrs.: no other century is not leap yr 100 yrs= 24 leap yrs * 76 ord yrs 1 leap yrs= 2 0dd days ord yrs= 1 0dd days 100= 24*2+ 76 =124/7 =5 odd days
there are about 70 0dd not realy surer im at the floor 67 then at the top groudon
1 is odd. An even number can be divided evenly, even though some elementary math teachers consider it even.
No. The sum of 1 odd number and 1 even number must always be odd.
You want: P(even) * P(even) * P(even) * P(even). P(even) = 3/6 or 1/2. Therefore probability even on 4 rolls is: 1/2 * 1/2 * 1/2 * 1/2 = 1/16 = 0.0625.
When a die is cast half the possible numbers are even. Therefore the probability is:Probability that die 1 is even = 1/2Probability that die 2 is even = 1/2Probability that both are even = 1/2 * 1/2 = 1/4.
1 in 4. Your choices are to have an odd or even total, which is a 1 in 2 chance. In order to get an even number, you have to have both die even or odd. So that cuts the 1 in 2 in half, giving you a 1 in 4 chance of both dice being even. (1 in 2 for even times 1 in 2 both even gives you 1 in 4.)
Any odd number is of the form 2n + 1. Adding two of these, call them a and b, will give even numbers (a-1) + 1 and (b-1) + 1. Since you then have 2 even numbers plus (1 +1), you have another even nunmber.
-- The first odd number is some even number plus an extra ' 1 '. -- The second odd number is some even number plus an extra ' 1 '. -- Add them. You get (an even number) + (an even number) + ( 2 ). That's an even number. ======================== Another mind-bending , brain-busting way to look at it : -- The first odd number is some even number plus an extra ' 1 '. -- The second odd number is some even number minus ' 1 '. -- Add them. You get (an even number) + (an even number) + ( [1 - 1] or zero ). That's an even number.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
The two dice can be (odd, odd), (odd, even), (even, odd), or (even, even). Thus the probability of two dice totaling an even number is 2*(1/2)*(1/2) = 1/2. 50/50