The "i" in 3i means the number is imaginary.
3i where i is the square root of negative one.3i x 3i = -9
The conjugate of (84-3i) is (84+3i). This gives you a real number when multiplied.
Use the rules of division for complex numbers. Just divide 1 / (4 + 3i). This requires multiplying numerator and denominator of this fraction by (4 - 3i), to get a real number in the denominator.
0 + 3i
The "i" in 3i means the number is imaginary.
11
No. It is an imaginary (or complex) number.
3i where i is the square root of negative one.3i x 3i = -9
The conjugate is 7 - 3i is 7 + 3i.
The complex conjugate of a number in the form a + bi is simply the same number with the sign of the imaginary part changed. In this case, the number is 7 + 3i, so its complex conjugate would be 7 - 3i. This is because the complex conjugate reflects the number across the real axis on the complex plane.
[7 - 3i] To find the conjugate: the sign of the real part stays the same, and the sign of the imaginary part is reversed. So the conjugate of [7 + 3i] is [7 - 3i]
The conjugate of (84-3i) is (84+3i). This gives you a real number when multiplied.
To form the additive inverse, negate all parts of the complex number → 8 + 3i → -8 - 3i The sum of a number and its additive inverse is 0: (8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.
- 2 - 3i
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9
Use the rules of division for complex numbers. Just divide 1 / (4 + 3i). This requires multiplying numerator and denominator of this fraction by (4 - 3i), to get a real number in the denominator.