18.02775638 feet
multiply the base of the triangle by the height then halve the answer.
Using Pythagoras' Theorum: (height)^2 = (hypotenuse)^2 - (base)^2
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
The two sides are called base and height and the sloping part of the right angle triangle is called the hypotenuse.
Yes, in an acute-angled triangle, the altitude and median can be the same for a specific vertex. This occurs when the triangle is isosceles, where the altitude from the vertex opposite the base not only serves as the height but also bisects the base, acting as the median. However, this is not generally true for all acute-angled triangles.
1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
multiply the base of the triangle by the height then halve the answer.
An isosceles, possibly equilateral, triangle
Using Pythagoras' Theorum: (height)^2 = (hypotenuse)^2 - (base)^2
area = base * height / 2;
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
Multiply the area by two then divide by the height - assuming that it is a right angled triangle.
height*height+base*base=hypotnuse*hypotnuse where hypotenuse is the longest side in a right angled triangle
The two sides are called base and height and the sloping part of the right angle triangle is called the hypotenuse.
The area of a triangle is one half base times height. In the case of a right triangle, the base is one leg and the height is the other leg. (The two legs being separated by the right angle.)
Yes, in an acute-angled triangle, the altitude and median can be the same for a specific vertex. This occurs when the triangle is isosceles, where the altitude from the vertex opposite the base not only serves as the height but also bisects the base, acting as the median. However, this is not generally true for all acute-angled triangles.
Any value that you like. There is no limit to how small not how large it can be.