35k^2 - 22k + 3 = 0
The factors of 35 are 1, 5, 7, 35
The factors of 3 are 1, 3
We need to multiply two factors which add to a sum of 22
As we can see, 3*5 + 1*7 will add to 22.
However we need -22, which is easily fixed by changing the signs of two of the factors: -3*5 + -1*7 = -22
so to factor the equation would be
(7k-3)(5k-1)=0
To find solutions to the equation, set each expression in the equation equal to 0.
7k-3=0
7k=3
k=3/7
5k-1=0
5k=1
k=1/5
So, k= 3/7 or 1/5
Solve using the quadratic formula
(3x+4)(3x-4)=0 x=±4/3
It can be solved by using the quadratic equation formula.
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
x2+x-15 = 0 Using the quadratic equation formula: x = 3.405124838 or x = -4.405124838
Solve using the quadratic formula
(3x+4)(3x-4)=0 x=±4/3
It can be solved by using the quadratic equation formula.
Using the quadratic equation formula: x = 8.42 or x = -1.42
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
x2+x-15 = 0 Using the quadratic equation formula: x = 3.405124838 or x = -4.405124838
-34
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
It is easier to solve a quadratic equation by factoring when the equation can be expressed as a product of two binomials that easily yield integer roots. This method is often quicker for simpler quadratics with small coefficients. In contrast, using a table to find solutions can be more cumbersome and time-consuming, particularly for equations where the roots are not integers or when the quadratic is more complex. Thus, factoring is preferred when the equation allows for straightforward factorization.
(x-12)2 using perfect square
x^2 = 64 x = +,- square root of 64 = +,- 8. Thus, x = -8 or x = 8
35k2 - 22k + 3 = 0 35k2 - 15k - 7k + 3 = 0 5k(7k - 3) - (7k - 3) = 0 (5k - 1)(7k - 3) = 0 5k -1 = 0 or 7k - 3 = 0 5k = 1 or 7k = 3 k = 1/5 or k = 3/7