35k^2 - 22k + 3 = 0
The factors of 35 are 1, 5, 7, 35
The factors of 3 are 1, 3
We need to multiply two factors which add to a sum of 22
As we can see, 3*5 + 1*7 will add to 22.
However we need -22, which is easily fixed by changing the signs of two of the factors: -3*5 + -1*7 = -22
so to factor the equation would be
(7k-3)(5k-1)=0
To find solutions to the equation, set each expression in the equation equal to 0.
7k-3=0
7k=3
k=3/7
5k-1=0
5k=1
k=1/5
So, k= 3/7 or 1/5
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Solve using the quadratic formula
(3x+4)(3x-4)=0 x=±4/3
It can be solved by using the quadratic equation formula.
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
x2+x-15 = 0 Using the quadratic equation formula: x = 3.405124838 or x = -4.405124838