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Find an equation of the line containing the given point and having the given slope 3-6m1?
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
What is the equation through point 0 negative 1 perpendicular to y equals 2x plus 5?
Given Point: (0,-1) Given Line: y=2x+5 If the line you are trying to find the equation of is perpendicular to the line given then the slope of the line you are trying to find must be the negative reciprocal of the line given. The slope of the line given is 2 so the slope of the line perpendicular to this one is -1/2. Using y=mx+b we get that y=(-1/2)x+b. Then we must use the point that was given to find b (the y-intercept). This means: -1=(-1/2)(0)+b -1=b So the equation is y=(-1/2)x-1
What is the point-slope form of a line with slope that contains the point (-2 1)?
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
What is the equation of a line that passes through the point 1 2 and is parallel to the x-axis?
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
Which is the equation of the line 3 1 and 0 0?
I assume that is a straight line between point (0, 0) and point (3, 1): The equation of any line is given by: y - yo = m(x - xo) where m is the gradient given by: m = (y1 - yo)/(x1 - x0) Thus, line is: y - 0 = (1 - 0)/(3 - 0)(x - 0) ⇒ y = 1/3 x or 3y = x
