(2, -3)
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates. In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5). Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5. We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5. Therefore, the coordinates of point B are (-2.5, -4.5).
Not too sure of the question but if A is (1, 2) and B is (-3, -1) then it is a right angle triangle if the coordinates of C are at (1, -1) or (-3, 2)
If the original point was (-4, 12) then the image is (-16, 48).
In Cartesian coordinates:(x - a)2 + (y - b)2 = R2(a, b) is the center-point of the circleR is the circle's radius.
They are (a, b-4).
Point A has coordinates (x,y). Point B (Point A rotated 270°) has coordinates (y,-x). Point C (horizontal image of Point B) has coordinates (-y,-x).
That would depend on its original coordinates and in which direction clockwise or anti clockwise of which information has not been given.
(2, -6)
(2, -4)
B is (-5, 9).
it is nothing
They are (-a, b).
If you are dilating the image about some factor, you can multiply coordinates by the constant. For instance... ½(1,2) = (½,½ * 2) = (½, 1)
(1, -2)
(2, -3)
i think -6,3