They are -10, -4, 2, 8, 14 and 20.
They are -2, 2, 6, 10 and 14.
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.
8
In simple terms, it doesn't matter. x<6 is the same as 6>x.
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
They are -2, 2, 6, 10 and 14.
123456
-2,-4,-6.
Sum of 1st 2 terms, A2 = 2 + 4 = 6 Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12 Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20 you can create a formula for the sum of the 1st n terms of this sequence Sum of 1st n terms of this sequence = n2 + n so the sum of the first 48 terms of the sequence is 482 + 48 = 2352
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.
8
In simple terms, it doesn't matter. x<6 is the same as 6>x.
They are: 6 15 24 33 and 42
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
If you want to know how to square a trinomial, you should first know the basic. (a+b+c)^2=? you have to square the first three terms then multiply 2 to the last three terms. All you have to do is to remember that a square of trinomial has 6 terms in the answer
It means you divide the first number of the problem by 7, then multiply that by 6. There is your answer.
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24