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because sin(2x) = 2sin(x)cos(x)

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15y ago

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Prove that sin theta power 8 - cos theta power 8 equal to sin sq Theta -cos sq x 1-sin sq Theta cos sq theta?

The equation cannot be proved because of the scattered parts.


How do you simplify tan theta cos theta?

Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).


What does negative sine squared plus cosine squared equal?

-Sin^(2)(Theta) + Cos^(2)Theta => Cos^(2)Theta - Sin^(2)Theta Factor (Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta)) #Is the Pythagorean factors . Or -Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1 Substitute Cos^(2)Thetqa - 1 + Cos^(2) Theta = 2Cos^(2)Theta - 1


How do you simplify cos theta times csc theta divided by tan theta?

'csc' = 1/sin'tan' = sin/cosSo it must follow that(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2


What trigonometric value is equal to cos 62?

The solution is found by applying the definition of complementary trig functions: Cos (&Theta) = sin (90°-&Theta) cos (62°) = sin (90°-62°) Therefore the solution is sin 28°.


De Morgan's law in complex number?

(Sin theta + cos theta)^n= sin n theta + cos n theta


What is the identity for tan theta?

The identity for tan(theta) is sin(theta)/cos(theta).


What is sin theta cos theta?

It's 1/2 of sin(2 theta) .


In which quardant are the terminal arms of the angle lie when sin thita is less then zero and cos thita is greater then zero?

The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant


If cos and theta 0.65 what is the value of sin and theta?

You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.


What is the derivative of sin under root theta?

The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))


What is sec theta - 1 over sec theta?

Let 'theta' = A [as 'A' is easier to type] sec A - 1/(sec A) = 1/(cos A) - cos A = (1 - cos^2 A)/(cos A) = (sin^2 A)/(cos A) = (tan A)*(sin A) Then you can swap back the 'A' with theta