I will assume that we are taking d/dx, not d/dn. There are two ways to interpret what you asked. First way is (sinx)^(2n). Second way is sin(x^(2n)). First answer: 2n(sinx)^(2n-1)(cosx)=2ncosx(sinx)^(2n-1). Second answer: cos(x^(2n))(2nx^(2n-1)).
When n=53, then 2n + 1 = 107
It is a statement that is equivalent to the equation:(2n+1)*(2n+3) = (2n+1)+(2n+3) + 23.
A Mersenne prime has the form 2n-1. For 2n-1 to be prime, n must also be prime. Perfect numbers have the form 2n-1(2n-1) where 2n-1 is a Mersenne prime, so when a new Mersenne prime is discovered, another perfect number is also found.
5-2n=3 -2n=3-5 -2n=-2 n=1
6=(1-2n)+5 6-5=(1-2n)+5-5 1=1-2n 1-1=1-1-2n 0=-2n 0/-2=-2n/-2 0=n
No. of subsets = 2n - 1 3 = 2n - 1 3 + 1 = 2n - 1 + 1 4 = 2n 4/2 = 2n/2 2/1 = 1n/1 2 = n n = 2elements
2n-butoxy1ethanol = 1
2n-1 to the tenth term = 1
1
(2n + 1)^2 -1
I will assume that we are taking d/dx, not d/dn. There are two ways to interpret what you asked. First way is (sinx)^(2n). Second way is sin(x^(2n)). First answer: 2n(sinx)^(2n-1)(cosx)=2ncosx(sinx)^(2n-1). Second answer: cos(x^(2n))(2nx^(2n-1)).
Answer is 3, 5, 7, 9detailsassume the numbers are2n-3, 2n-1, 2n+1, 2n+3 ......................... (1)(2n-3) 2 + (2n-1) 2 + (2n+1) 2 + (2n+3) 2 = 16416n 2 + 20 = 16416n 2 = 144n2 = 9n = 3Substitute in eq 1 we get the answer above
If: 2n = 1 Then: n = 1/2 or 0.5
The nth hexagonal number is given by the formula: hn = 2n * (2n - 1) / 2
odd x even = even (2n + 1)(2n) = 2[n(2n + 1)] let n(2n + 1) = t = 2t (even)
When n=53, then 2n + 1 = 107