Oh honey, "3r 12" doesn't quite make sense. I think you might have mixed up your math lingo there. If you're looking to solve an equation involving "3r" and "12," we need a bit more information to get to the bottom of it. Just remember, math is like a recipe - you gotta have all the right ingredients to make it work.
7r = 3r - 527r (- 3r) = 3r - 52 (- 3r)4r = - 524r / 4 = -52 / 4r = -13
What you want to do is to try and get all the variables on one side by adding/subtracting. Then get the numbers on the other side and solve.
17 = 13 - 3r Subtract 13 from bith sides: 4 = -3r Divide both sides by -3 : -4/3 = r or r = -1.3...
3r + 3r + 2t = 6r + 2t
(3r - 2)(3r - 2) or (3r - 2) squared.
how do i solve -3r+3r=-6(7+7r)-7(4-7r)
7r = 3r - 527r (- 3r) = 3r - 52 (- 3r)4r = - 524r / 4 = -52 / 4r = -13
3r-r equals 12 = -9
If that's 3r + 12, that factors to 3(r + 4)
What you want to do is to try and get all the variables on one side by adding/subtracting. Then get the numbers on the other side and solve.
17 = 13 - 3r Subtract 13 from bith sides: 4 = -3r Divide both sides by -3 : -4/3 = r or r = -1.3...
3r - 9r = 18 wright equaton -6r = 18 combine like terms r = -3 solve
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
(3r + 18)/12 = (4r - 48)/4Multiply both sides by 12: (3r + 18) = 3*(4r - 48)or: 3r + 18 = 12r - 144Subtract 3r from both sides: 18 = 9r - 144Add 144 to both sides: 162 = 9rDivide both sides by 9: 18 = rAnswer: r = 18
3r + 3r + 2t = 6r + 2t
The factors of 3 are 1 and 3 The factors of 12 are 1, 2, 3, 4, 6, and 12 The factors of 18 are 1, 2, 3, 6, 9, and 18
It is 12r - 20 or 4*(3r - 5)