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What is the polynomial roots to 1 5i and -3i?
4
2 plus 5i plus 6 plus 3i?
I assume that "I" is a variable2+5i+6+3i7i+6+3i10i+616i is the answer
How do you solve 2 divided by 5i?
0.4
What are some imaginary numbers?
i is the Imaginary Unit, equal to sqrt(-1). So i and any real number multiplied by i will all be imaginary numbers. Here are some: i, -i, 5i, -3i, i*pi, etc.
What is the square root of -25 divided by suqare root of 9 minus square root of-1?
[ sqrt(-25) / sqrt(9) ] - [ sqrt(-1) ] = j5/3 - j1 = j 2/3
What is conjugate of 2 3i 2-5i?
The conjugate of 2 + 3i is 2 - 3i, and the conjugate of 2 - 5i is 2 + 5i.
How do you subtract imaginary numbers?
When adding and subtracting complex numbers, you can treat the "i" as any variable. For example, 5i + 3i = 8i, 5i -3i = 2i, etc.; (2 + 5i) - (3 - 3i) = (2 - 3) + (5 + 3)i = -1 + 8i.
What is the polynomial roots to 1 5i and -3i?
4
If 3i 2 5i x 6i then x?
negative 15 is the answer
What is complex conjugate for the number 9-5i?
The conjugate is 7 - 3i is 7 + 3i.
2 plus 5i plus 6 plus 3i?
I assume that "I" is a variable2+5i+6+3i7i+6+3i10i+616i is the answer
Plot the number in a complex plane -1-3i?
2
Let A equals 1 plus 2i and let C equals 5 plus 5i what is A-C?
-4-3i
What are 10 complex numbers with the absolute value of 5?
Use the Pythagorean theorem. 5, -5, 5i, and -5i will work, as well as any combination of a real and imaginary number such that (real part) squared + (imaginary part) squared = 25, for example, 4 + 3i, 3 + 4i, 4 - 3i, etc.
How do you solve 2 divided by 5i?
0.4
What is 1 divided by 2 plus 5i in the form a plus bi?
1/(2 + 5i) (multiply both the numerator and the denominator by 2 - 5i)= 1(2 - 5i)/(2 + 5i)(2 - 5i)= (2 - 5i)/(4 - 25i2) (substitute -1 for i2)= (2 - 5i)/(4 + 25)= (2 - 5i)/29= 2/29 - (5/29)i
What are some imaginary numbers?
i is the Imaginary Unit, equal to sqrt(-1). So i and any real number multiplied by i will all be imaginary numbers. Here are some: i, -i, 5i, -3i, i*pi, etc.
