There is none. An integer has to be a number with no decimal places
A nonzero integer does not have a multiplicative inverse that is also an integer. The multiplicative inverse of an integer ( n ) is ( \frac{1}{n} ), which is only an integer if ( n ) is ( 1 ) or ( -1 ). For all other nonzero integers, the result is a rational number, not an integer. Therefore, only ( 1 ) and ( -1 ) have multiplicative inverses that are integers.
A factor.
The set of nonzero integers is not closed under division. This is because dividing one nonzero integer by another can result in a non-integer. For example, ( 1 \div 2 = 0.5 ), which is not an integer. Therefore, the result of the division is not guaranteed to be a member of the set of nonzero integers.
an integer
In division by three, possible nonzero remainders are 1 and 2.
A nonzero integer does not have a multiplicative inverse that is also an integer. The multiplicative inverse of an integer ( n ) is ( \frac{1}{n} ), which is only an integer if ( n ) is ( 1 ) or ( -1 ). For all other nonzero integers, the result is a rational number, not an integer. Therefore, only ( 1 ) and ( -1 ) have multiplicative inverses that are integers.
Yes, when a nonzero integer is divided by it's opposite it's value equals -1
if p is an integer and q is a nonzero integer
A factor.
The set of nonzero integers is not closed under division. This is because dividing one nonzero integer by another can result in a non-integer. For example, ( 1 \div 2 = 0.5 ), which is not an integer. Therefore, the result of the division is not guaranteed to be a member of the set of nonzero integers.
A rational number is always the result of dividing an integer when the divisor is nonzero.
No.
an integer
In division by three, possible nonzero remainders are 1 and 2.
2
Yes, because a zero integer is simply 0
Yes, it is.