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It is simply an equation with non-rational solutions. There is no special name for it.

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Q: What is an equation that has two radical expressions and no real roots?
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Related questions

How many real roots do we have if the polynomial equation is in degree six?

Such an equation has a total of six roots; the number of real roots must needs be even. Thus, depending on the specific equation, the number of real roots may be zero, two, four, or six.


Is radical 25 a real number?

If by "radical" you mean "square root of", then yes. Both square roots of 25 are real numbers.


A quadratic equation has how many real roots?

Quadratics can two, one or no real roots.


What is an example radical equation of real life?

secret lang


What is true about a quadratic equation when the discriminant of the equation is positive?

It will then have 2 different roots If the discriminant is zero than it will have have 2 equal roots


If the discriminant is negative the equation has?

No real roots but the roots are a pair of complex conjugates.


How many real roots exist if the discriminant of the eqation0?

If the discriminant of a quadratic equation is 0 then it has two equal real roots.


What are the roots of quadratic equation?

That depends on the value of its discriminant if its less than zero then it has no real roots.


What are quadratic equations with real roots?

If the discriminant of the quadratic equation is zero then it will have 2 equal roots. If the discriminant of the quadratic equation is greater than zero then it will have 2 different roots. If the discriminant of the quadratic equation is less than zero then it will have no roots.


How do you find the discriminant and number of real solutions to a quadratic equation?

The equation ax^2 + bx + c = 0 where a, b and c are real and a is non-zero has discriminant D = b^2 &ndash; 4ac. Then,if D > 0 the equation has two real roots which are distinct;if D = 0 the equation has two real roots which are coincident;if D < 0 the equation has two roots which form a complex conjugate pair (advanced mathematics only).


What determines how many solutions a quadric equation will have and whether they are real or imaginary?

If you put the equation into standard form, ax2 + bx + c = 0, then the number and type of roots are determined by the expression b2 - 4ac - this is because in the quadratic equation, this appears under a radical sign. If this expression is...Positive: the equation has two real solutions.Zero: the equation has one solution, sometimes considered a "double root".Negative: the equation has two complex solutions.


What does the discriminant tell us about the nature of the roots?

The equation ax^2 + bx + c = 0 where a, b and c are real and a is non-zero has discriminant D = b^2 &ndash; 4ac. Then,if D > 0 the equation has two real roots which are distinct;if D = 0 the equation has two real roots which are coincident;if D < 0 the equation has two roots which form a complex conjugate pair (advanced mathematics only).