Due to the rubbish browser that we are compelled to use, it is not possible to use any super or subscripts so here goes, with things spelled out in detail: log to base 2a of 2b = log to base a of 2b/log to base a of 2a = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + (log to base a of a)] = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + 1]
Example 27=n3 : Take the cube root of 27. In general find the log, divide it by the power, then take the antilog.
11011 base 2 is equal to 27 in base 10 321 base 4 is equal to 57 in base 10 27+57=84
log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006
log37 - log3x = 4 log3(7/x) = 4 7/x = 34 = 81 x = 7/81
Log base 3 of 81 is equal to 4, because 3 ^ 4 = 81. Therefore, two times log base 3 of 81 is equal to 2 x 4 = 8.
The logarithm base 4 of 16 is asking the question "4 raised to what power equals 16?" In this case, 4 squared is equal to 16, so the answer is 2. Therefore, log base 4 of 16 is equal to 2.
If log644 = x, then 64x = 4. The cubed root of 64 (which is the same as 641/3) is 4, so log base 64 of 4 is 1/3.
Due to the rubbish browser that we are compelled to use, it is not possible to use any super or subscripts so here goes, with things spelled out in detail: log to base 2a of 2b = log to base a of 2b/log to base a of 2a = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + (log to base a of a)] = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + 1]
log325 + log34 = log3(25*4) = log3(100) = log10100/log103 = 2/log103
log 100 base e = log 100 base 10 / log e base 10 log 100 base 10 = 10g 10^2 base 10 = 2 log 10 base 10 = 2 log e base 10 = 0.434294 (calculator) log 100 base e = 2/0.434294 = 4.605175
Example 27=n3 : Take the cube root of 27. In general find the log, divide it by the power, then take the antilog.
11011 base 2 is equal to 27 in base 10 321 base 4 is equal to 57 in base 10 27+57=84
9x = 27 log(9) + log(x) = log(27) log(x) = log(27) - log(9) log(x) = log(27/9) 10log(x) = 10log(27/9) x = 27/9 x = 3 This strikes us as the method by which the federal government might solve the given equation ... after appointing commissions to study the environmental impact and recommend a method of solution, of course.
log base 2 of [x/(x - 23)]
The log of infinity, to any base, is infinity.
log base e = ln.