If log644 = x, then 64x = 4. The cubed root of 64 (which is the same as 641/3) is 4, so log base 64 of 4 is 1/3.
log(e)100 = log(10)100 / log(10)e = log(10)100 / log(10) 2.71828.... = 2/ 0.43429448... = 4.605170186..... (The answer). NB Note the change of log base to '10' However, on a calculator type in ;- 'ln' (NOT log). '100' '=' The answer shown os 4.605....
The browser which is used for posting questions is almost totally useless for mathematical questions since it blocks most symbols.I am assuming that your question is about log base 3 of (x plus 1) plus log base 2 of (x-1).{log[(x + 1)^log2} + {log[(x - 1)^log3}/log(3^log2) where all the logs are to the same base - whichever you want. The denominator can also be written as log(3^log2)This can be simplified (?) to log{[(x + 1)^log2*(x - 1)^log3}/log(3^log2).As mentioned above, the expression can be to any base and so the expression becomesin base 2: log{[(x + 1)*(x - 1)^log3}/log(3) andin base 3: log{[(x + 1)^log2*(x - 1)}/log(2)
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
Use the equation. ln 'x' = log(2) x / log(2) n. '2' being the binary system of 10101010.... However, it may be easier to understand using base '10'. lnx' = log(10)x / log(10)'e' NB This will give a different answer to log base '2' (binary). NNB Within logarithms you can change the base value tp any other base using the above equation. Calculators give logs to base '10'(log) and base 'e' (2.71828.....)(ln). However, you can use any number as a base value e.g. '100' say , or '79' say. providing you use the above eq'n.
You can convert to the same base, by the identity: logab = log b / log a (where the latter two logs are in any base, but both in the same base).
Log base 3 of 81 is equal to 4, because 3 ^ 4 = 81. Therefore, two times log base 3 of 81 is equal to 2 x 4 = 8.
If we take the logarithm of both sides, then it is log(4^x) = log(128). Then from logarithm rules, this can be changed to: x*log(4) = log(128), then x = log(128)/log(4). You can punch this into a calculator and get the answer, but what if we use log base 2, we don't need a calculator. So log2(4) = 2, because 2² = 4. And log2(128) = 7, because 2^7 = 128. So we have x = 7/2 = 3.5, then you can check your answer: 4^3.5 = (4^3)*(4^.5). So 4 cubed = 64, and 4 raised to the 1/2 power is the square root of 4, which is 2. So 64 times 2 = 128.
You can calculate that on any scientific calculator - like the calculator on Windows (if you change the options, to display as a scientific calculator). Log base 4 of 27 is the same as log 27 / log 4. You can use logarithms in any base to calculate that - just use the same base for both logarithms.
Log4 64=y 64=4y 26=22y Therefore y=3
4 is the base, 3 is the exponent. Answer = 4 to power 3 = 64
The logarithm base 4 of 16 is asking the question "4 raised to what power equals 16?" In this case, 4 squared is equal to 16, so the answer is 2. Therefore, log base 4 of 16 is equal to 2.
64 Base = Percentage/Rate Base = 16/25% = 16/0.25 = 64 thus; 25% of 64 is equal to 16.
log325 + log34 = log3(25*4) = log3(100) = log10100/log103 = 2/log103
Due to the rubbish browser that we are compelled to use, it is not possible to use any super or subscripts so here goes, with things spelled out in detail: log to base 2a of 2b = log to base a of 2b/log to base a of 2a = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + (log to base a of a)] = [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + 1]
4x4x4=base 4 with the exponent 3 or 64
It is a 4*4 square.
64(:Juliana Abel(: