Given a set of n scores, the variance is sum of the squared deviation divided by n or n-1. We divide by n for the population and n-1 for the sample.
Take any positive integer n. If you square it, and subtract 1, you get (x squared - 1). If you take (n - 1) and (n + 1), and multiply them together, you get n squared - n + n - 1, which is the same as (n squared - 1).
n x n2 = n3
n=number x 1 and n2 is n x n
3 squared is 9 and so 9n = 63 which means n = 7
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
Oh, dude, adding n squared plus n squared is like adding apples to apples, you know? It's just like, you take two n squared terms and you add them together to get 2n squared. It's not rocket science, man. Just double up those n squares and you're good to go.
If that's n squared, the multiples are n squared, 2 n squared, 3 n squared and so on. If that's n + 2, the multiples are n + 2, 2n + 4, 3n + 6 and so on.
Oh, dude, N squared is just a fancy way of saying you multiply a number by itself. So, like, if N is 3, then N squared is 3 times 3, which equals 9. It's like math's way of saying, "Hey, let's make this more confusing than it needs to be."
Simple equation lad. In your example, you said n=4 and x= n squared + n - 1 + (n-2)squared + (n-3)squared. You simply write n²+n-1+(n-2)²+(n-3)² I hope that is what you mean by what you say. P.S. To get the to the power of sign, hold alt and press 0178 for ², and 0179 for ³
(n*n)+n
n^3 mean a number Squared by 3
Given a set of n scores, the variance is sum of the squared deviation divided by n or n-1. We divide by n for the population and n-1 for the sample.
Oh honey, that's just n times n minus n. So, n squared minus n is just n times (n-1). Hope that clears things up for ya, darling.
Take any positive integer n. If you square it, and subtract 1, you get (x squared - 1). If you take (n - 1) and (n + 1), and multiply them together, you get n squared - n + n - 1, which is the same as (n squared - 1).
n x n2 = n3
n=number x 1 and n2 is n x n