Since CotΘ = 1 / tanΘ, then tanΘ / cotΘ = tanΘ / (1/tanΘ) = tanΘ x tanΘ = tan²Θ
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whats the big doubt,cot/tan+1= 1+1= 2
cot theta=tan(90-tetha)
The identity for tan(theta) is sin(theta)/cos(theta).
The Answer is 1 coz, 1-Tan squarex = Cot square X. So cot square x divided cot square x is equal to 1
tan (theta x theta) : must square the value of the angle, theta, before applying the trig function, tangent.