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Since CotΘ = 1 / tanΘ, then tanΘ / cotΘ = tanΘ / (1/tanΘ) = tanΘ x tanΘ = tan²Θ

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12y ago

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How can you verify 1 plus tan theta divided by 1 minus tan theta equals cot theta plus 1 divided by cot theta minus 1?

It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.


What is cot theta divided by tan theta plus one equal?

whats the big doubt,cot/tan+1= 1+1= 2


How do you simplify sin theta times csc theta divided by tan theta?

Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).


If tan Theta equals 2 with Theta in Quadrant 3 find cot Theta?

Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.


If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?

tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2


What is tan theta minus cot theta?

-2(cot2theta)


Tan theta plus cot theta equals 2csc2 theta?

Yes, it is.


What can the function cotangent theta also be expressed as?

cot theta=tan(90-tetha)


Express csc theta in terms of cot theta theta is in quadrant 3?

It is -sqrt(1 + cot^2 theta)


How do you simplify csc theta cot theta cos theta?

cosec(q)*cot(q)*cos(q) = 1/sin(q)*cot(q)*cos(q) = cot2(q)


Csc divided by cot squared equals tan multiplied by sec?

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What is cot theta 1.5 sin theta?

The expression "cot theta = 1.5 sin theta" can be rewritten using the definitions of trigonometric functions. Since cotangent is the reciprocal of tangent, we have cot(theta) = cos(theta) / sin(theta). Therefore, the equation becomes cos(theta) / sin(theta) = 1.5 sin(theta), leading to cos(theta) = 1.5 sin^2(theta). This relationship can be used to find specific values of theta that satisfy the equation.