whats the big doubt,cot/tan+1= 1+1= 2
cot theta=tan(90-tetha)
The identity for tan(theta) is sin(theta)/cos(theta).
The Answer is 1 coz, 1-Tan squarex = Cot square X. So cot square x divided cot square x is equal to 1
tan (theta x theta) : must square the value of the angle, theta, before applying the trig function, tangent.
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
whats the big doubt,cot/tan+1= 1+1= 2
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
-2(cot2theta)
Yes, it is.
cot theta=tan(90-tetha)
It is -sqrt(1 + cot^2 theta)
cosec(q)*cot(q)*cos(q) = 1/sin(q)*cot(q)*cos(q) = cot2(q)
Yes.
The identity for tan(theta) is sin(theta)/cos(theta).