It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
Yes, it is.
whats the big doubt,cot/tan+1= 1+1= 2
cot theta=tan(90-tetha)
Tan^2
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
Since CotΘ = 1 / tanΘ, then tanΘ / cotΘ = tanΘ / (1/tanΘ) = tanΘ x tanΘ = tan²Θ
It is -sqrt(1 + cot^2 theta)
It also equals 13 12.
cosec(q)*cot(q)*cos(q) = 1/sin(q)*cot(q)*cos(q) = cot2(q)