The first four terms are 3 9 27 81 and 729 is the 6th term.
If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46
Any number you like.If you fit a linear equation, Un = 24 - 11n then the 6th term is 42.However,Vn = (-29x4 + 290x3 - 1015x2 + 790x + 744)/60 gives the sequence 13, 2, -9, -20, -42.6, and -100Wn = (7x4 - 70x3 + 245x2 - 570x + 648)/20 gives the sequence 13, 2, -9, -20, -22.6, and 0whileXn = (71x4 - 710x3 + 2485x2 - 4210x + 3144)/60 gives the sequence 13, 2, -9, -20, -2.6, and 100By suitable choice of polynomial, any number at all can be in sixth place.
There are infinitely many formulae that generate that sequence for the first 5 terms, but then give different terms for the 6th and onwards. However, the simplest formula (and the one that I guess your teacher is expecting) is based on the fact that there is a fixed common difference of 6 between terms, giving t(n) = 6n - 4 for n = 1, 2, 3, ...
To find the 8th term in the sequence 15, 24, 42, 78, 150, we first identify a pattern in the differences between consecutive terms. The differences are 9, 18, 36, and 72, which suggest that the differences themselves are doubling (approximately). Continuing this pattern, the next differences would be 144 and 288. Thus, the 6th term would be 150 + 144 = 294, the 7th term would be 294 + 288 = 582, and the 8th term would be 582 + 576 = 1158. Therefore, the 8th term is 1158.
If you mean 6, 18, 54 then the 6th term is 1456 because each term is 3 times greater than the previous term
the answer is 8
To find the first term and common ratio of a geometric progression, we can use the formula for the nth term of a geometric sequence: (a_n = a_1 \times r^{(n-1)}). Given that the 6th term is 160 and the 9th term is 1280, we can set up two equations using these values. From the 6th term, we get (a_1 \times r^5 = 160), and from the 9th term, we get (a_1 \times r^8 = 1280). By dividing the two equations, we can eliminate (a_1) and solve for the common ratio (r).
The first four terms are 3 9 27 81 and 729 is the 6th term.
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
Apply Euclid's Division Lemma(or in simple words Division Algorithm) to 1024 and 181: 1024 = 181 x 5 + 119 181 goes 5 times into 1024 with remainder 119. It means if we subtract 1024 from the 6th multiple of 181 then we get the required which is to be added to 1024. Way of obtaining 6th multiple: (This method is useful when we deal with large numbers!) If we subtract 119 from 1024 then we get 5th multiple of 181. 1024 - 119 = 905. And on adding 181 to 905 we get the 6th multiple of 181. 181 + 905 = 1086. And 1086 - 1024 = 64 is the required number.
If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 12, 20, 28, 36, and 44. These are increasing by 8 each time. This means the second difference is constant, indicating a quadratic sequence. By calculating the second difference, we can determine the equation for the nth term. The nth term for this sequence is n^2 + 10.
It is x6.
Any number you like.If you fit a linear equation, Un = 24 - 11n then the 6th term is 42.However,Vn = (-29x4 + 290x3 - 1015x2 + 790x + 744)/60 gives the sequence 13, 2, -9, -20, -42.6, and -100Wn = (7x4 - 70x3 + 245x2 - 570x + 648)/20 gives the sequence 13, 2, -9, -20, -22.6, and 0whileXn = (71x4 - 710x3 + 2485x2 - 4210x + 3144)/60 gives the sequence 13, 2, -9, -20, -2.6, and 100By suitable choice of polynomial, any number at all can be in sixth place.
The 6th number of the Fibonacci sequence is 8.0 + 0 = 00 + 1 = 11 + 1 = 21 + 2 = 32 + 3 = 53 + 5 = 8Notice how it is the 6th equation meaning its the 6th Fibonacci number.Note that some people like to use 1 twice instead of 0.http://en.wikipedia.org/wiki/Fibonacci_number