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The first four terms are 3 9 27 81 and 729 is the 6th term.
If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46
Any number you like.If you fit a linear equation, Un = 24 - 11n then the 6th term is 42.However,Vn = (-29x4 + 290x3 - 1015x2 + 790x + 744)/60 gives the sequence 13, 2, -9, -20, -42.6, and -100Wn = (7x4 - 70x3 + 245x2 - 570x + 648)/20 gives the sequence 13, 2, -9, -20, -22.6, and 0whileXn = (71x4 - 710x3 + 2485x2 - 4210x + 3144)/60 gives the sequence 13, 2, -9, -20, -2.6, and 100By suitable choice of polynomial, any number at all can be in sixth place.
There are infinitely many formulae that generate that sequence for the first 5 terms, but then give different terms for the 6th and onwards. However, the simplest formula (and the one that I guess your teacher is expecting) is based on the fact that there is a fixed common difference of 6 between terms, giving t(n) = 6n - 4 for n = 1, 2, 3, ...
The question seems to be incorrect because, if the definition is 2n + 3 then the third tern should be 9 and the fourth one 11. In that case, t(6) = 2*6 + 3 = 12+3 = 15
If you mean 6, 18, 54 then the 6th term is 1456 because each term is 3 times greater than the previous term
the answer is 8
The first four terms are 3 9 27 81 and 729 is the 6th term.
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
Apply Euclid's Division Lemma(or in simple words Division Algorithm) to 1024 and 181: 1024 = 181 x 5 + 119 181 goes 5 times into 1024 with remainder 119. It means if we subtract 1024 from the 6th multiple of 181 then we get the required which is to be added to 1024. Way of obtaining 6th multiple: (This method is useful when we deal with large numbers!) If we subtract 119 from 1024 then we get 5th multiple of 181. 1024 - 119 = 905. And on adding 181 to 905 we get the 6th multiple of 181. 181 + 905 = 1086. And 1086 - 1024 = 64 is the required number.
If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
ar5 = 160 ar8 = 1280 so r3 = 1280/160 = 8 and so r = 2 then, ar5 = 160 gives a = 160/32 = 5 First term = a = 5 Common ratio = r = 2
It is x6.
Any number you like.If you fit a linear equation, Un = 24 - 11n then the 6th term is 42.However,Vn = (-29x4 + 290x3 - 1015x2 + 790x + 744)/60 gives the sequence 13, 2, -9, -20, -42.6, and -100Wn = (7x4 - 70x3 + 245x2 - 570x + 648)/20 gives the sequence 13, 2, -9, -20, -22.6, and 0whileXn = (71x4 - 710x3 + 2485x2 - 4210x + 3144)/60 gives the sequence 13, 2, -9, -20, -2.6, and 100By suitable choice of polynomial, any number at all can be in sixth place.
The 6th number of the Fibonacci sequence is 8.0 + 0 = 00 + 1 = 11 + 1 = 21 + 2 = 32 + 3 = 53 + 5 = 8Notice how it is the 6th equation meaning its the 6th Fibonacci number.Note that some people like to use 1 twice instead of 0.http://en.wikipedia.org/wiki/Fibonacci_number
There are infinitely many formulae that generate that sequence for the first 5 terms, but then give different terms for the 6th and onwards. However, the simplest formula (and the one that I guess your teacher is expecting) is based on the fact that there is a fixed common difference of 6 between terms, giving t(n) = 6n - 4 for n = 1, 2, 3, ...