X2 -11x +10=(x - 1 )(x - 10)
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
You take 11x10 then by 2...
-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)
(x + 2)(x - 12)
x2 - 11x + 24 = (x - 3)(x - 8)
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
x2 -11x-12= (x-12)(x+1)
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
21
x2 + 11x + 24 You want the equation to be in the form (x + a)(x + b), where the two solutions are -a and -b.You know that...ab = 24...and...a + b = 11Note that 8 times 3 is 24, and 8 plus 3 is 11.x2 + 11x + 24 = (x + 3)(x + 8)The two answers are x = -3 and x = -8.
x(6x - 11)
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
It is: x^2 +11x +24 = (x+8)(x+3) when factored
x + 35 doesn't factor. If you meant x2 + 11x + 24, the answer is (x + 8)(x + 3)
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
Can you improve the question? It's hard to tell what you mean.