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x+xy=8 xy=-x+8 y=-1+8/x
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
2+2y+x+xy=(x+2)(y+1)
This equation does not equal a number, but it can be factorised. x2-xy-20y2=(x-5y)(x+4y)
y = 1/2 x - 3/2
Oh, what a happy little question! To factor out xy from xy, you simply take out the common factor, which is xy itself. So, the factored form of xy is just xy. Isn't that just lovely? Just remember, there are no mistakes in math, only happy little accidents.
The GCF is xy
x+xy=8 xy=-x+8 y=-1+8/x
xy = x ÷x y = 1
If x - 3y = 12, we can solve for x in terms of y: x = 12 + 3y. Then, to find xy, we multiply x by y: xy = y(12+3y) = 12y + 3y^2.
It is XY^2 or X*Y*Y
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
Divide by 'x'; x2+xy/x = x(x+y)
(x-y) + (xy - 1) = (x - 1)(y + 1)
*Hint*=xy=x mutiplied by y.