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x+xy=8 xy=-x+8 y=-1+8/x
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
2+2y+x+xy=(x+2)(y+1)
This equation does not equal a number, but it can be factorised. x2-xy-20y2=(x-5y)(x+4y)
y = 1/2 x - 3/2
xy + x = x(y + 1)
The GCF is xy
x+xy=8 xy=-x+8 y=-1+8/x
xy = x ÷x y = 1
If x - 3y = 12, we can solve for x in terms of y: x = 12 + 3y. Then, to find xy, we multiply x by y: xy = y(12+3y) = 12y + 3y^2.
It is XY^2 or X*Y*Y
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
(x-y) + (xy - 1) = (x - 1)(y + 1)
*Hint*=xy=x mutiplied by y.
Divide by 'x'; x2+xy/x = x(x+y)