∫ (x2+3) = ∫x2 + ∫3(1/3)X3 + 3X + C
2
4x
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
negative sin(x)
The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps
The anti-derivative of sqrt(x) : sqrt(x)=x^(1/2) The anti-derivative is x^(1/2+1) /(1/2+1) = (2/3) x^(3/2) The anti-derivative is 4e^x is 4 e^x ( I hope you meant e to the power x) The anti-derivative of -sin(x) is cos(x) Adding, the anti-derivative is (2/3) x^(3/2) + 4 e^x + cos(x) + C
∫ (x2+3) = ∫x2 + ∫3(1/3)X3 + 3X + C
The derivative of 2x2 + 4x + 8 is 4x+4.
the derivative from scribit that means holy writing is scripture
x = 10x, so derivative = 10
2
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
9x2
4x
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
negative sin(x)