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The complex number of the equation z = x + iy is x.

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โˆ™ 2014-11-11 21:33:31
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Q: What is the complex number of z 2 - Ii?
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The sum of a complex number and its conjugate?

Given a complex number z = a + bi, the conjugate z* = a - bi, so z + z*= a + bi + a - bi = 2*a. Note that a and b are both real numbers, and i is the imaginary unit: +sqrt(-1).

Why complex no is denoted by z?

There are no real reason why it is denoted by z, but that the real number axis is denoted by x, imaginary number is denoted by y, the real part of a complex number is denoted by a, the imaginary part of a complex number is denoted by b, so there is z left.

What is mode of z in complex no?

In complex mode functions, modules, and procedures cannot operate. For a complex number z = x + yi, first define the absolute value. This would be |z| and is the distance from z to 0 in the complex plane.

If in a complex number the modulus of z 3 is less or equal to 8 then find the minimum of modulus of z - 2?

The possible values of z are (a cis b), where a is any number between and including 0 and 2 and b is any of 0, 60, 120, 180, 240 and 300 degrees. The minimum modulus of z - 2, that is |z - 2|, is 0.

Which is the polar form what complex number z equals 3add square root 3i?


Is the variable z is often used to denote a complex number?

Yes and it is z=x+iy

What is used to divide complex numbers?

You can use another complex number, a real number or an imaginary number. Complex number equations make interesting images. The link shows the image produced by (z-1)/(z+1) and inverses the checkerboard around two points.

How do you convert the complex number minus i into polar form?

A COMPLEX NUMBER CAN BE CONVERTED INTO A POLAR FORM LET US TAKE COMPLEX NUMBER BE Z=a+ib a is the real number and b is the imaginary number THEN MOD OF Z IS SQUARE ROOT OF a2+b2 MOD OF Z CAN ALSO BE REPRESENTED BY r . THEN THE MOD AMPLITUDE FORM IS r(cos@Very interesting, but -i is not a complex no. it is a simple (imaginary) no. with no real part.

Is the product of two conjugate complex number always a real number?

Yes. This can be verified by using a "generic" complex number, and multiplying it by its conjugate: (a + bi)(a - bi) = a2 -abi + abi + b2i2 = a2 - b2 Alternative proof: I'm going to use the * notation for complex conjugate. Any complex number w is real if and only if w=w*. Let z be a complex number. Let w = zz*. We want to prove that w*=w. This is what we get: w* = (zz*)* = z*z** (for any u and v, (uv)* = u* v*) = z*z = w

Why and what is principle argument of complex number?

A complex number (z = x + iy) can be plotted the x-y plane if we consider the complex number the point (x,y) (where x is the real part, and y is the imaginary part). So once you plot the complex number on the x-y plane, draw a line from the point to the origin. The Principle Argument of z (denoted by Arg z) is the measure of the angle from the x-axis to the line (made from connecting the point to (0,0)) in the interval (-pi, pi]. The difference between the arg z and Arg z is that arg z is an countably infinite set. And the Arg z is an element of arg z. Why? : The principle argument is needed to change a complex number in to polar representation. Polar representation makes multiplication of complex numbers very easy. z^2 is pretty simple: just multiply out (x+iy)(x+iy). But what about z^100? This is were polar represenation helps us, and to get into this representation we need the principle argument. I hope that helped.

when a complex number z is written in its polar form, z = r (cos(theta) + i * sin(theta)), the nonnegative number r is called the or modulus, or z?


In a series rl circuit when XL increases and r remains the same z will?

z=rl +XL in a series circuit. if XL increases and r remains the same, z will increase. z is a complex number and the magnitude is z=(r^2 + (XL)^2)^.5. if the vector part of z increases z increases.

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