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d/dx [ 5 sin(2x) ] = 10 cos (2x)

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12y ago

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What is the derivative of root sin2x?

You are supposed to use the chain rule for this. First step: derivative of root of sin2x is (1 / (2 root of sin 2x)) times the derivative of sin 2x. Second step: derivative of sin 2x is cos 2x times the derivative of 2x. Third step: derivative of 2x is 2. Finally, you need to multiply all the parts together.


What is the derivative of cos 2x?

f'(x)=-sin2x(2) f'(x)=-2sin2x First do the derivative of cos u, which is -sin u. Then because of the chain rule, you have to take the derivative of what's inside and the derivative of 2x is 2.


What is the derivative of 1 divided by sinx?

y=1/sinxy'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)y'=(sinx*0-1(cosx))/(sin2x)y'=(-cosx)/(sin2x)y'=-(cosx/sinx)*(1/sinx)y'=-cotx*cscx


Is sin2x equal to sin2x?

sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!


Why does -2sinxcosx equal -sin2x?

-4


How do you prove one - tan square x divided by one plus tan square xequal to cos two x?

(1 - tan2x)/(1 + tan2x) = (1 - sin2x/cos2x)/(1 + sin2x/cos2x) = (cos2x - sin2x)/(cos2x + sin2x) = (cos2x - sin2x)/1 = (cos2x - sin2x) = cos(2x)


What is the derivative of 5x?

The derivative of 5x is 5.


Sin2x - radical 2 cosx equals 0?

Sin2x = radical 2


What is the derivative of 5secx?

You can take out any constant from a derivative. In other words, this is the same as 5 times the derivative of sec x.


What value is equivalent to 1 - cosx squared?

sin2x because sin2x + cos2x = 1


What does sin2x - 1 equal?

1


How does 1 plus cot squared x equals csc squared x?

The proof of this trig identity relies on the pythagorean trig identity, the most famous trig identity of all time: sin2x + cos2x = 1, or 1 - cos2x = sin2x. 1 + cot2x = csc2x 1 = csc2x - cot2x 1 = 1/sin2x - cos2x/sin2x 1 = (1 - cos2x)/sin2x ...using the pythagorean trig identity... 1 = sin2x/sin2x 1 = 1 So this is less of a proof and more of a verification.