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Subjects>Math>Math & Arithmetic

What is the derivative of 5x lnx?

Anonymous

∙ 14y ago

Updated: 11/4/2022

If that is a simple product, just use the product rule.

If there is a power involved - that is not always clear in the question - you must use logarithmic differenciation.

Wiki User

∙ 14y ago

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Derivative of lnx?

1/X

What is the derivative of y equals xln x?

(xlnx)' = lnx + 1

What is the derivative and second derivative of lnx to the third power?

If you mean: y =(lnx)3 then: dy/dx = [3(lnx)2]/x ddy/dx = [(6lnx / x) - 3(lnx)2] / x2 If you mean: y = ln(x3) Then: dy/dx = 3x2/x3 = 3/x = 3x-1 ddy/dx = -3x-2 = -3/x2

What is the derivative of ln 1 plus x?

d/dx of lnx is 1/x Therefore the derivative is 1/(1+x)

What is the derivative of lnx raised to 4?

ln(x4)?d/dx(ln(u))=1/u*d/dx(u)d/dx(ln(x4))=[1/x4]*d/dx(x4)-The derivative of x4 is:d/dx(x4)=4x4-1d/dx(x4)=4x3d/dx(ln(x4))=[1/x4]*(4x3)d/dx(ln(x4))=4x3/x4d/dx(ln(x4))=4/x(lnx)4?Chain rule: d/dx(ux)=x(u)x-1*d/dx(u)d/dx(lnx)4=4(lnx)4-1*d/dx(lnx)d/dx(lnx)4=4(lnx)3*d/dx(lnx)-The derivative of lnx is:d/dx(ln(u))=1/u*d/dx(u)d/dx(lnx)=1/x*d/dx(x)d/dx(lnx)=1/x*(1)d/dx(lnx)=1/xd/dx(lnx)4=4(lnx)3*(1/x)d/dx(lnx)4=4(lnx)3/x

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