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Find the length of the diagonal of a rectangle that has a length of 16 ft and width of 10 ft?
18.9 feet
What is the diagonal measurement of 40' X 50'?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
The length of a rectangle is 2 cm and the width is 3 cm Find the length of the diagonal?
The diagonal is 3.61cm
What is the length of a diagonal rectangle with a length of 9 inches and a width of 3 inches?
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
What is the diagonal feet of a 30x40 building?
Ah, let's paint a happy little picture here! To find the diagonal of a rectangle, we can use the Pythagorean theorem. So for a 30x40 building, we can calculate the diagonal using the formula: √(30^2 + 40^2) = √(900 + 1600) = √2500 = 50 feet. Just like that, we've added a lovely diagonal to our building!
A rectangle is 4 ft by 6ft What is the length of the diagonal of the rectangle?
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. In this case, the diagonal forms the hypotenuse of a right triangle with the sides being the length and width of the rectangle. So, the diagonal (d) can be calculated as d = √(4^2 + 6^2) = √(16 + 36) = √52 ≈ 7.21 feet.
Find the length of the diagonal of a rectangle that has a length of 16 ft. and width of 10 ft.?
18.9 feet
What is the diagonal measurement of a square 24 feet x 36 feet?
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
What is diagonal measurement of 30 foot by 32 foot rectangle?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle with sides of 30 feet and 32 feet, the diagonal (d) can be calculated as (d = \sqrt{30^2 + 32^2}). This gives (d = \sqrt{900 + 1024} = \sqrt{1924}), which simplifies to approximately 43.9 feet.
What is the diagonal measurement for a rectangle 420 feet long and 75 feet wide?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. The formula is ( d = \sqrt{l^2 + w^2} ), where ( l ) is the length and ( w ) is the width. For a rectangle that is 420 feet long and 75 feet wide, the diagonal is calculated as ( d = \sqrt{420^2 + 75^2} ), which equals approximately 425.6 feet.
Find the length of the diagonal of a rectangle that has a length of 16 ft and width of 10 ft?
18.9 feet
What is the diagonal measurement of 16 FT x 38 FT?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
How do your find the diagonal measurement for 120 by 150?
If they are the dimensions of a rectangle then use Pythagoras' theorem to find the length of the diagonal.
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
How do you count the number of squares crossed by the diagonal in a rectangle?
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
What is the diagonal measurement of 40' X 50'?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
How do i do this problem the sum of the squares of the measures of all sides of a rectangle is 648 Find the measure of a diagonal of the rectangle?
2w^2 + 2l^2 = 648. So we have w^2 + l^2 = 324. The diagonal is sqrt(w^2 + l^2) = sqrt(324) = 18.
