The diagonal is 25 feet.
18.9 feet
The diagonal is 3.61cm
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
240 sq m
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
18.9 feet
18.9 feet
If they are the dimensions of a rectangle then use Pythagoras' theorem to find the length of the diagonal.
2w^2 + 2l^2 = 648. So we have w^2 + l^2 = 324. The diagonal is sqrt(w^2 + l^2) = sqrt(324) = 18.
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
The diagonal is 3.61cm
Diagonal of a rectangle or square = square root of ( length2 + width2 )
Pythagorean theorm!!
By the Pythagorean Theorem, the diagonal is the hypotenuse of the right triangle formed by the diagonal and the two included sides. c2 = a2 + b2 so the diagonal is the square root of the sum of the squares of the rectangle's length and width. Example : for a rectangle 4 x 3, the diagonal is sqrt(32 + 42) = sqrt (25) = 5
You need to use trigonometry cosine (angle) = length/diagonal diagonal = length/cos(angle)