answersLogoWhite

0

To solve this use Pythagorean Theorem (a²+b²=c²)

(13-(-5))²+(24-11)²=c²

18²+13²=c²

324+169=c²

493=c²

So the answer is the square root of 493

and that rounded to 2 decimals is 22.20

User Avatar

Wiki User

15y ago

What else can I help you with?

Related Questions

What is the distance between the points 2116 and 911?

If you mean points of (21, 16) and (9, 11) then the distance works out as 13


What is the distance between the points (2116) and (911)?

If you mean points of (21, 16) and (9, 11) then the distance works out as 13


What is the distance between the points 21 16 and 9 11?

Distance2 = (21-9)2 + (16-11)2 = 169 and the square root of this is the distance which is 13 units


What is the distance between the points (-5 -2) and (3 13)?

Points: (-5, -2) and (3, 13)Distance works out as 17 units


What is the distance between the points -8 4 and 54?

If you mean: (-8, 4) and (5, 4) Then the distance between the points works out as 13


What is the distance between the points (21) and (146) on a coordinate plane?

If you mean points of: (2, 1) and (14, 6) then the distance is 13


What is the distance between the points 3 5 and 1 8?

(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points


If a(-1-3)and b(11-8)what is the length of ab?

If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units


What is the distance between the points (45) and (1013) on a coordinate plane?

If you mean points of (4, 5) and (10, 13) then the distance works out as 10


What is the distance between the points (2 1) and (14 6) on a coordinate plane?

Points: (2, 1) and (14, 6) Distance: 13


What is the distance between the points (-4 5) and (3 16)?

Points: (-4, 5) and (3, 16) Distance: square root of 170 which is about 13


What is the distance between the points (-7 -13) and (8 -5)?

To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.