In an arithmetic sequence, the first term is the starting value, and the common difference is the amount added to each subsequent term. If the first term is 2 and the common difference is 3, the sequence begins with 2 and each following term is obtained by adding 3. Thus, the sequence would be 2, 5, 8, 11, and so on. The nth term can be calculated using the formula: ( a_n = 2 + (n-1) \times 3 ).
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The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).
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The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
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The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
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The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).
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Placing a question mark at the end of some phrases does not make it a sensible question.
If the first term, t(1) = a and the common difference is r then t(n) = a + (n-1)*r where n = 1, 2, 3, ...
The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
The sequence you are describing is an arithmetic sequence, where each term is generated by adding a constant value, known as the common difference, to the previous term. For example, if the first term is 3 and the common difference is 2, the sequence would be 3, 5, 7, 9, and so on. This method of generating terms highlights the linear nature of arithmetic sequences. The formula for the nth term can be expressed as ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference.
Ah, what a lovely sequence you have there! To find the nth term, you notice that each number is increasing by 2. So, if we start at 6, the nth term can be represented by the formula 2n + 4. Happy calculating, my friend!