-8
-8
36
t(n) = a + 8*d = 54 .. .. .. .. .. .. .. (A) s(12) = 12*a + 66*d = 438 .. .. .. .. (B) 12*(A) - (B) => 12*A + 96*d -12*A - 66*D = 648 - 438 => 30*d = 210 = d = 7 Then substituting this value in (A) gives a + 54 = 54 => a = -2 So the first term is -2 and the common difference is 7.
Oh, dude, it's like a pattern party! So, to find the nth term for this sequence, you first need to figure out the pattern. Looks like each number is decreasing by 2. So, the nth term would be 13 - 2n. Easy peasy, right?
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6
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
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Placing a question mark at the end of some phrases does not make it a sensible question.
If the first term, t(1) = a and the common difference is r then t(n) = a + (n-1)*r where n = 1, 2, 3, ...
The given sequence 6, 8, 10, 12 is an arithmetic sequence with a common difference of 2 between each term. To find the nth term of an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 6 and the common difference (d) is 2. So, the nth term (a_n = 6 + (n-1)2 = 2n + 4).
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
To find the sum of all even numbers from 2 through 200, we can use the formula for the sum of an arithmetic series. Since the sequence is an arithmetic sequence with a common difference of 2, we can calculate the number of terms using the formula ((last term - first term) / common difference) + 1. In this case, the first term is 2, the last term is 200, and the common difference is 2. Plugging these values into the formula gives us ((200 - 2) / 2) + 1 = 100. The sum of an arithmetic series is given by the formula n/2 * (first term + last term), so the sum of all even numbers from 2 through 200 is 100/2 * (2 + 200) = 10100.
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.