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The indefinite integral of sin 2x is

-cos 2x / 2 + C, where C is any constant.

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Q: What is the indefinte integral of sin2x?
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Cos x sin x integral?

sin2x + c


Is sin2x equal to sin2x?

sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!


How do you prove one - tan square x divided by one plus tan square xequal to cos two x?

(1 - tan2x)/(1 + tan2x) = (1 - sin2x/cos2x)/(1 + sin2x/cos2x) = (cos2x - sin2x)/(cos2x + sin2x) = (cos2x - sin2x)/1 = (cos2x - sin2x) = cos(2x)


What value is equivalent to 1 - cosx squared?

sin2x because sin2x + cos2x = 1


What is the integral of sin x squared all divided by x?

The Web site integrals.wolfram.com gives the following:integral of sin2x/x = (1/2) (log x - Ci(2 x))Ci is the cosine integral, a special function. Look at the site for a more detailed description.What this really means is that this integral can NOT be solved with the so-called elementary functions, i.e., using only polynomials, roots, trigonometric functions, natural logarithms, and the inverses of some of these.The Web site integrals.wolfram.com gives the following:integral of sin2x/x = (1/2) (log x - Ci(2 x))Ci is the cosine integral, a special function. Look at the site for a more detailed description.What this really means is that this integral can NOT be solved with the so-called elementary functions, i.e., using only polynomials, roots, trigonometric functions, natural logarithms, and the inverses of some of these.The Web site integrals.wolfram.com gives the following:integral of sin2x/x = (1/2) (log x - Ci(2 x))Ci is the cosine integral, a special function. Look at the site for a more detailed description.What this really means is that this integral can NOT be solved with the so-called elementary functions, i.e., using only polynomials, roots, trigonometric functions, natural logarithms, and the inverses of some of these.The Web site integrals.wolfram.com gives the following:integral of sin2x/x = (1/2) (log x - Ci(2 x))Ci is the cosine integral, a special function. Look at the site for a more detailed description.What this really means is that this integral can NOT be solved with the so-called elementary functions, i.e., using only polynomials, roots, trigonometric functions, natural logarithms, and the inverses of some of these.