The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
Well, darling, it looks like we have a arithmetic sequence going on here. The common difference between each term is 7, so to find the nth term, you can use the formula a_n = a_1 + (n-1)d. In this case, a_1 is 1 and d is 7, so the nth term would be 1 + (n-1)7, which simplifies to 7n - 6. Voila!
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
15(1)
1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
t(n) = 29 - 7n where n = 1, 2, 3, ...
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
The nth term is 4n-1 and so the next term will be 19
The nth term is 22n and so the next number will be 5*22 = 110
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
Well, darling, it looks like we have a arithmetic sequence going on here. The common difference between each term is 7, so to find the nth term, you can use the formula a_n = a_1 + (n-1)d. In this case, a_1 is 1 and d is 7, so the nth term would be 1 + (n-1)7, which simplifies to 7n - 6. Voila!
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
x2-3=n
15(1)