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What is the nth term if the sequence is 22 15 8 1 -6?

It is: nth term = 29-7n


What is the nth term of the arithmetic sequence 22 15 8 1 ...?

The nth term is -7n+29 and so the next term will be -6


What is the nth term of 8 15 22 29 36?

The sequence 8, 15, 22, 29, 36 is an arithmetic sequence where each term increases by 7. The first term (a) is 8, and the common difference (d) is 7. The nth term can be expressed using the formula: ( a_n = a + (n-1) \cdot d ). Therefore, the nth term is ( a_n = 8 + (n-1) \cdot 7 = 7n + 1 ).


What is the nth term for 22 15 8 1 -6?

t(n) = 29 - 7n where n = 1, 2, 3, ...


What is the nth term in 1 3 7 11 15?

If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19


What is the nth term of 1 -3 -7 -11 and -15?

It is: nth term = 5-4n and so the next term will be -19


What is the nth term in the sequence 3 7 11 15?

The nth term is 4n-1 and so the next term will be 19


What is the nth term of 1-2-4-8-16?

The nth term is 22n and so the next number will be 5*22 = 110


What is the nth term for the sequence 1 6 13 22 33?

The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).


What is the nth term of 1 8 15 22 29?

Oh, dude, okay, so the nth term of 1, 8, 15, 22, 29 is basically adding 7 each time. So, if you want the nth term, you just take the first term, which is 1, and then add 7 times n-1. Like, it's that simple. Math can be chill sometimes, you know?


What is the nth term for 3 7 11 15?

The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.


What is the nth term for -1 5 15 29 47 69?

To find the nth term of the sequence -1, 5, 15, 29, 47, 69, we first observe the differences between consecutive terms: 6, 10, 14, 18, 22. The second differences are constant at 4, indicating a quadratic relationship. The general form for the nth term can be expressed as ( an^2 + bn + c ). By solving the system of equations formed by substituting n=1, 2, and 3, we find the nth term is ( 2n^2 + 2n - 3 ).