To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
29 x 47 = 1363
29 and 47 are prime.
17, 19, 23, 29, 31, 37, 41, 43, and 47
If you mean: 14 29 32 47 55 64 then 29 and 47 are prime numbers
9n+2
To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
It is T(n) = n2 + 4*n + 2.
Well, darling, the nth term for this sequence is 8n + 7. You just add 8 to each term to get the next one, simple as that. So, if you want the 100th term, just plug in n=100 and you'll get 807. Easy peasy lemon squeezy!
four hundred and nity six
81
t(n) = n2 + 5n - 3
To find the nth term of a sequence, we first need to find the pattern or rule that governs the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 6, 10, 14, 18, and so on. This means that the nth term is given by the formula n^2 + 4, where n represents the position of the term in the sequence.
1 3 4 7 11 18 29 47 76 123 199 .......and so on Add together the previous two terms to find the next term i.e 1+3=4, 3+4=7, 4+7=11
One possible answer is t(n) = (n5 - 10n4 + 55n3 - 110n2 +364n)/60
29 x 47 = 1363
29