To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 9, then 13, then 17, and so on. This pattern indicates that the nth term is given by the formula n^2 + n - 1. So, the nth term of the sequence 0, 9, 22, 39, 60 is n^2 + n - 1.
The sequence given consists of the squares of the natural numbers: (1^2, 2^2, 3^2, 4^2, 5^2, 6^2, 7^2, 8^2, 9^2). To find the nth term of the sequence, you can use the formula (n^2), where (n) is the position in the sequence. Therefore, the nth term is (n^2).
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Strangely enough, it is 9n + 1 for n = 1, 2, 3, ...
Triangular numbers are numbers in the sequence 1, 1+2, 1+2+3, 1+2+3+4. This sequence can be represented by triangles as follows: (very crude figure with an even cruder browser!)xxxxxxxxxxxxxxxxxxxxand so on.The nth term of this sequence is n*(n+1)/2.Triangular numbers are numbers in the sequence 1, 1+2, 1+2+3, 1+2+3+4. This sequence can be represented by triangles as follows: (very crude figure with an even cruder browser!)xxxxxxxxxxxxxxxxxxxxand so on.The nth term of this sequence is n*(n+1)/2.
The nth term of the sequence is 3n - 2.
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
The nth term of the sequence is (n + 1)2 + 2.
12 - 5(n-1)
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
the nth term of the sequence 98, 94, 88, 80 can be expressed as 98 - (n - 1) * 2.
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 9, then 13, then 17, and so on. This pattern indicates that the nth term is given by the formula n^2 + n - 1. So, the nth term of the sequence 0, 9, 22, 39, 60 is n^2 + n - 1.
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
2 + ((6 + 2 * (n - 1) * (n - 1))
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
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