Assuming they are fair, regular dice, the probability is 1/18.
First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
Tossing a coin ten times is a [repeated] experiment or trial. It is neither empirical nor theoretical probability.
50% chance
Assuming they are fair, regular dice, the probability is 1/18.
It is 7/12.
25%
First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.
If using regular dice, the probability is 0 since the minimum sum from four dice is 4.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
Tossing a coin ten times is a [repeated] experiment or trial. It is neither empirical nor theoretical probability.
The probability for that is (1/2)4 = 1/16.
50% chance
1/6
The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.
Depends on if you are talking about probability. If so then yes. If not then 100 coins is more than 1 coin.