{2}
Restate the question: what is the range of y=2?
On an x-y grid, the equation y=2 represents a horizontal line which crosses the y-axis at 2.
The domain (the set of possible x-values) is the set of real numbers.
The range (the set of y-values you get when you plug in the x-values) is just 2, since the y- value is 2 eeverywhere on the line.
if you mean y=(x+2)/x, the range is all reals except y=1 If you mean y=x+2/x, the range is (-inf, -2sqrt(2)] U [2sqrt(2),+inf)
7
y = -2x² + x y = -2 [ x² - (x/2) ] y = -2 [ x² - (x/2) + (1/4) ] + (1/2) y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2) Hence, the Range of y is : -∞ < y ≤ (1/2). It can be written as the interval ( -∞, 1/2 ]. ........ Ans. _____________________________________ Happy To Help ! _____________________________________
y=x^2
y ∈ ℜ
if you mean y=(x+2)/x, the range is all reals except y=1 If you mean y=x+2/x, the range is (-inf, -2sqrt(2)] U [2sqrt(2),+inf)
If you mean y =9x^2 -4 , than the range is the possible y values. Range = 0<= y < infinity.
7
Domain (input or 'x' values): -∞ < x < ∞.Range (output or 'y' values): -2 ≤ y ≤ 2.
y = -2x² + x y = -2 [ x² - (x/2) ] y = -2 [ x² - (x/2) + (1/4) ] + (1/2) y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2) Hence, the Range of y is : -∞ < y ≤ (1/2). It can be written as the interval ( -∞, 1/2 ]. ........ Ans. _____________________________________ Happy To Help ! _____________________________________
The answer will range between '2' & '-2' Reason; The Sine function ranges between '1' & '-1' , so if it has a coefficient of '2', this will increase the range to '2' & '-2'.
y=x^2
The range is 2.
y ∈ ℜ
y < 1
It is y >= 5.
yes y=x Like 2=2