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Let the two numbers be ( x ) and ( y ). Since the mean is 10, we have ( \frac{x + y}{2} = 10 ), which simplifies to ( x + y = 20 ). Given that the range is 4, we can express it as ( y - x = 4 ). Solving these two equations, we find ( x = 8 ) and ( y = 12 ).
y = -2x² + x y = -2 [ x² - (x/2) ] y = -2 [ x² - (x/2) + (1/4) ] + (1/2) y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2) Hence, the Range of y is : -∞ < y ≤ (1/2). It can be written as the interval ( -∞, 1/2 ]. ........ Ans. _____________________________________ Happy To Help ! _____________________________________
Prime factor both numbers or expressions and use the factors the number of times it was used the MOST in either number. 6y^3=2*3*y*y*y 18y^4=2*3*3*y*y*y*y 2*3*3*y*y*y*y=18y^4
y=|x|/4 The range is [0 , ∞ )
To find the range of ordered pairs, identify all the second elements (y-values) in each ordered pair. List these y-values without duplication to obtain the range. For example, if the ordered pairs are (1, 2), (3, 4), and (5, 2), the range would be {2, 4}. This represents all the unique outputs (y-values) from the given pairs.
If you mean y =9x^2 -4 , than the range is the possible y values. Range = 0<= y < infinity.
(x^2)^(1/2) equals x, therefore, y = x+4, which has a range and domain of all real numbers. The graph is a straight line, slope of 1, y-intercept of 4. Are you actually saying y = (x^2+4)^(1/2). If so, the range and domain will also be all real numbers because x^2+4 will never result in a negative number.
Call your number 10x + y. x = y + 2 and 10x + y = 4 + 6(x + y) Substitute y + 2 for x: 10(y + 2) + y = 4 + 6((y + 2) + y) This simplifies to 10y + 20 + y = 4 + 6y + 12 + 6y, ie 20 - 16 = 12y - 11y so y = 4 and x = 6 Your number is 64, which is indeed 4 more than the sum of its digits.
To find the domain or range, solve for a variable and see if the other variable has any restrictions on it. In this case, x2 + y = 4 y = 4 - x2 There are no restrictions on x, therefore x is in the domain of all real numbers. x = square root(4 - y) Since the argument (number in brackets) of a square root must be positive, 4 - y > 0, y < 4. Domain: x can be all real numbers. Range: y can be all real numbers less than or equal to 4.
As there are two numbers, the range is the difference between themAs there are 2 numbers the mean is exactly in the middle of them.Thus half the range is less than the mean and half the range is greater than the mean.Thus the two numbers are 10 ± (4/2) = 10 ± 2 = 8 and 12.Algebraically, this can be seen:Let the two numbers be x and y with y > xThen:their range is y - x = 4; andtheir mean is (x + y) / 2 = 10{2} can be rearrange to give x + y = 10 × 2 → y + x = 20adding {3} to {1} yields: (y + y) + (-x + x) = 20 + 4 → 2y = 24 → y = 12subtracting {1} from {3} yields (y - y) + (x - -x) = 20 - 4 → 2x = 16 → x = 8→ the two numbers are 8 and 12.
y = -2x² + x y = -2 [ x² - (x/2) ] y = -2 [ x² - (x/2) + (1/4) ] + (1/2) y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2) Hence, the Range of y is : -∞ < y ≤ (1/2). It can be written as the interval ( -∞, 1/2 ]. ........ Ans. _____________________________________ Happy To Help ! _____________________________________
If you take '2' and '4', then 2 is 50% of 4. To calculate that, use (2/4)*100 to get the percentage. So to find out what percentage number 'x' is of number 'y', use (x/y)*100.
Prime factor both numbers or expressions and use the factors the number of times it was used the MOST in either number. 6y^3=2*3*y*y*y 18y^4=2*3*3*y*y*y*y 2*3*3*y*y*y*y=18y^4
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
y=|x|/4 The range is [0 , ∞ )
F(x) = -x^2 - 4x + 5 This is a quadratic function of the form y = ax + by + c, whose graph is a parabola. So, a = -1, b = -4 and c = 5 Since a is negative the parabola opens downward, and the maximum valy of the function is equal to the value of the y-coordinate of the vertex. The x- coordinate of the vertex is x = -b/2a. So, x = -(-4)/[2(-1) = 4/-2 = -2 When x = -2, then y = -(-2)^2 - 4(-2) + 5 = -4 + 8 + 5 = 9 Thus, the range is all value of y, such that y ≤ 9, Equivalently, the range is {y| y ≤ 9} or [9, ∞).
x+y=6x^2 + y^2=20 x=2 and y=4 or vice versa