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y = -2x² + x y = -2 [ x² - (x/2) ] y = -2 [ x² - (x/2) + (1/4) ] + (1/2) y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2) Hence, the Range of y is : -∞ < y ≤ (1/2). It can be written as the interval ( -∞, 1/2 ]. ........ Ans. _____________________________________ Happy To Help ! _____________________________________
Prime factor both numbers or expressions and use the factors the number of times it was used the MOST in either number. 6y^3=2*3*y*y*y 18y^4=2*3*3*y*y*y*y 2*3*3*y*y*y*y=18y^4
y=|x|/4 The range is [0 , ∞ )
y=x+4 If you are tring to get "x" alone, you would do this: y=x+4 -4 -4 -------- y-4=x If you are trying to get "y" alone, then y=x+4 is your answer. Y and X represent the 'Unknown Number'. For example, Y might mean the number 6 and X means the number 2, so then Y equals the same amount as X + 4 does which, in my example, is 6 but the numbers value to the letters (what the letter replacing the number is) changes from equasion to equasion. Generaly, somewhere written on the sheet it may say Y = 6 so then you would have to find out what X means, which in my example, is 2.
The range of the function y=x^2 would be y is greater than or equal to 0 in this case. So pretty much just find the vertex of the function and what ever the y coordinate is set that as the lowest number for the range.