The 'n'th term is [ 13 + 5n ].
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.
(13 + 23)/2 = 18
13 - 14 - 18 - 23 - 32 = -74
Every next number is increased by 5. The next number in the sequence is 23.
8, 13, 18, 23, 28, etc.
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
Since the terms of the given sequence differ by different numbers, then the terms would start a new pattern, so that the other term of the sequence is 23.16 26 21 13 23 18 10...
(13 + 23)/2 = 18
The next number in the sequence would be 23. The sequence consists of prime numbers.
By subtracting one term from the next the common difference can be found: Using -8 and -13: -13 - -8 = 13 + 8 = -5 → Common difference is -5.