Answer: 2
A number is divisible by 3 if the sum of its digits is a multiple of 3.
Now 2+1+4=7. If we add 2 more it is 9 which is a multiple of 3.
So 216 is divisible by 3 since 2+1+6=9 which is a multiple of 3.
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
number to be added to 97 to get the smallest three digit number = 3smallest three digit number = 100100 - 97 = 3
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
5.
339 + 1 = 340,which is exactly divisible.
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341
Seven
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
number to be added to 97 to get the smallest three digit number = 3smallest three digit number = 100100 - 97 = 3
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
What number must be added to to make it equal to 190312
It is: 36 and so 960/48 = 20
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
Any number ending in 3.
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
Nope - 1038 is an even number and thus is divisible by 2. Its digits added together total 12 - which is divisible by 3... therefore the original number is also divisible by 3 !!