5050, according to the program I quickly whipped up.
Yes, 100 is divisible by 3. To determine if a number is divisible by 3, you can sum its digits. The sum of the digits in 100 is 1 + 0 + 0 = 1, which is not divisible by 3. Therefore, 100 is not divisible by 3.
The sum of the digits of the number 10 is calculated by adding its individual digits together. The digits in 10 are 1 and 0. Therefore, the sum is 1 + 0 = 1.
The factors of 3 are 1 and 3. The sum of the digits of these factors is calculated as follows: for 1, the sum of its digits is 1, and for 3, the sum of its digits is 3. Therefore, the total sum of the digits of the factors of 3 is 1 + 3 = 4.
5050 ie 101 x 50
5,050
100
The sum of the digits of the number 10 is calculated by adding its individual digits together. The digits in 10 are 1 and 0. Therefore, the sum is 1 + 0 = 1.
The factors of 3 are 1 and 3. The sum of the digits of these factors is calculated as follows: for 1, the sum of its digits is 1, and for 3, the sum of its digits is 3. Therefore, the total sum of the digits of the factors of 3 is 1 + 3 = 4.
1 + 1 = 2 The sum of the digits is therefore 2.
5050 ie 101 x 50
The sum of all the digits of all the positive integers that are less than 100 is 4,950.
Digits are from 1 to 9the sum of the 9 greatest digits is = 9+9+9+9+9+9+9+9+9 = 81the sum of the 9 lowest digits is = 1+1+1+1+1+1+1+1+1+1= 9and so :81 + 9 = 90
Since a dozen is 12, then the digits are 1 and 2. To get the sum, you simply add 1 + 2, which = 3.
5,050
1 + 23 + 4 + 5 + 67 = 100 is one way. 1 + 2 + 34 + 56 + 7 = 100 is another. 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 so you need to move two non-adjacent digits that sum to 8 into the tens' places. This is because: Start with a sum of 28 Lose two digits that sum to 8 from the units so that you have 28 - 8 = 20 Gain two digits that in the tens place that sum to 8 so that 20 + 80 = 100.
1+0 = 1
A dozen is equal to 12. The sum of the digits of 12 are 1 + 2 = 3.