(5x - 4)(2x + 7)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42
27x-3=105 27x =105+3 27x = 108 27x/27=108/27 x= 4
8-6+4=6. But 8-(6+4)=-2
(5x - 4)(2x + 7)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42
27x-3=105 27x =105+3 27x = 108 27x/27=108/27 x= 4
the answer is (3x-2)(9x squared+6x+4)
8-6+4=6. But 8-(6+4)=-2
No. The solution to the equation is 1/3. To solve: 27x - 5 = 4 (add 5 to each side to separate knownsa from inkowns) 27x = 9 (now divide both sides by 27 to find the value of x) x = 1/3 (solution)
cube root of 27 = 3, so 3^12 = 531 441 * * * * * If the question is about 27x, rather than 27, the answer is as follows: cuberoot(27x12) = (27x)12/3 = (27x)4 = 531441x4
Add 7x to each side: 136 = 27x + 20 Subtract 20 from each side: 116 = 27x Divide each side by 27: x = 116/27 = 4 & 8/27.
(4)(2)+7x-28+7x-27x-6.This expression cannot be simplified further nor solved (because it is not equal to anything).
9xy(3xy - 4)
20